Truth Table:
| A | B | C | F |
| 0 | 0 | 0 | 1 |
| 0 | 0 | 1 | 0 |
| 0 | 1 | 0 | 1 |
| 0 | 1 | 1 | 0 |
| 1 | 0 | 0 | 1 |
| 1 | 0 | 1 | 1 |
| 1 | 1 | 0 | 0 |
| 1 | 1 | 1 | 1 |
Here, input variable, n =3
So, selection variable, s=n-1=3-1=2
Here output variable is one so, we need one 2s×1 or 22×1 or 4×1 size multiplexer
Let us assume, B and C as selection variable. Now put A into the implementation table:
Implementation Table for output F:
| I0 | I1 | I2 | I3 | |
| A/ | 0 | 1 | 2 | 3 |
| A | 4 | 5 | 6 | 7 |
| 1 | A | A/ | A |
Circuit Diagram:
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